Oracle ORA-00604
https://blog.csdn.net/wdkymys/article/details/81358095
select b.file_name 物理文件名, b.tablespace_name 表空间, b.bytes/1024/1024 大小M, (b.bytes-sum(nvl(a.bytes,0)))/1024/1024 已使用M, substr((b.bytes-sum(nvl(a.bytes,0)))/(b.bytes)*100,1,5) 利用率 from dba_free_space a,dba_data_files b where a.file_id=b.file_id group by b.tablespace_name,b.file_name,b.bytes order by b.tablespace_name看到99%的利用率,就是天堂近了,該連絡DBA出來掃地了